Answer:
The value is [tex]} N = 66 \ blocks [/tex]
Explanation:
From the question we are told that
The weight of the block is [tex]W_b = 100 \ N[/tex]
The dimension of the block is [tex]d = 0.400 m \ X \ 0.250 \ m \ X \ 0.130 \ m[/tex]
Generally two atmosphere is equivalent to
[tex]P_{2atm} = 2 * 1.013 *10^{5} = 202600 \ N/m^2[/tex]
Generally 1 atm = [tex]1.013 *10^{5} N/m^2[/tex]
The area of the block would be evaluated using width and height because we need for the smaller surface to be in contact with the ground in order to maximize the pressure and minimize number of blocks
So
[tex]A = 0.250 * 0.130[/tex]
=> [tex]A = 0.0325 \ m^2 [/tex]
Generally the force due to this blocks is mathematically represented as
[tex]F = N * W_b[/tex]
Here N is the number of blocks
So
[tex]} 202600 = \frac{N * 100 }{ 0.0325}[/tex]
=> [tex]} N = 66 \ blocks [/tex]
