Respuesta :
Answer:
m = 31.284 grams
Explanation:
Given that,
The dimension of a magnesium block is 2.00 cm x 3.00 cm x 3.00 cm.
The density of magnesium is, d = 1.738 g/cm³
We need to find the mass of the magnesium block. We know that the density of an object is given by its mass per unit its volume. So,
[tex]d=\dfrac{m}{V}\\\\\text{Where m=mass}\\\\m=d\times V\\\\m=1.738\ g/cm^3\times (2\times 3\times 3)\ cm^3\\\\m=31.284\ \text{grams}[/tex]
So, the mass of the block is 31.284 grams.
The mass of a magnesium block is 31.284 grams.
- The calculation is as follows:
[tex]Density = mass \div volume\\\\ Mass = Density \times volume\\\\ = 1.738 \times ( 2.00 cm \times 3.00 cm \times 3.00 cm)[/tex]
= 31.284 grams
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