croco
contestada

Write an equation for the nth term of the arithmetic sequence.
Then find a50.

3, 9, 15, 21, . . .

Respuesta :

unicorn3125

Answer:

             [tex]\bold{a_n=6n-3}\\\\\bold{a_{50}=297}[/tex]

Step-by-step explanation:

3, 9, 15, 21,  ...

9-3 = 6;   15-9 = 6;   21-15 = 6   ⇒  d = 6

first term:  a = 3

difference:  d = 6

so the formula:

                         [tex]a_n=a+d(n-1)\\\\a_n=69+6(n-1)\\\\a_n =3+6n-6\\\\\underline{a_n=6n-3}[/tex]                        

and:

   [tex]a_{50}=6\cdot50-3=300-3=297[/tex]

Otras preguntas