Answer:
[tex]r=\dfrac{31}{3}[/tex]
Step-by-step explanation:
The problem says that G is any point lying on line segment DM. So,
DG = GM
We have, DG = and GM = 4r-28
Putting values in above equation
r +3 = 4r-28
Taking like terms together
r-4r = -28-3
-3r = -31
[tex]r=\dfrac{31}{3}[/tex]
So, the value of r is [tex]\dfrac{31}{3}[/tex]
