Answer:
1/8 (12.5 %)
Explanation:
Cross: IAi X IAIB
F1: 1/4 IAIA 1/4 IAIB 1/4 IAi 1/4 IBi
Phenotypes:
- IAIA and IAi >> type A blood
- IBi >> type B blood
- IAIB >> type AB blood
Phenotypic frequency type A blood: 1/2 (i.e., 1/4 IAIA + 1/4 IAi) >>
Probability to have 3 offspring with type A blood: 1/2 x 1/2 x 1/2 = 1/8
The human ABO blood group is a system consisting of there different alleles: A, B, and O. This system is used in genetics as an example of codominance because both A and B alleles are expressed in heterozygous individuals (i.e., IAIB), whereas only the allele A is expressed in individuals that have A and O alleles (since O allele is recessive to the A and B alleles).
The probability of having 3 offsprings with type A blood group = 0.125% or 1/8
In humans blood group system is called the ABO system blood type is controlled by the I locus. It has three alleles IA, IB, and i. Where The allele for A blood group is IA, the allele for B blood group is IB and the allele for O blood group is i.
Possible genotypic combinations for all four phenotypes:
Cross - IAi X IAIB
Punnett:
IA i
IA IAIA IAi
IB IAIB IBi
Thus, for one offspring the chances are 1:2
then for 3 offsprings = [tex]\frac{1}{2} \times \frac{1}{2} \times \frac{1}{2}[/tex]
= [tex]\frac{1}{8}[/tex]
The probability of having 3 offsprings with type A blood group = 0.125% or [tex]\frac{1}{8}[/tex]
Learn more about the ABO system:
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