A bee flies at 9 feet per second directly to a flowerbed from its hive. The bee stays at the flowerbed for 13 ​minutes, and then flies directly back to the hive at 6 feet per second. It is away from the hive for a total of 16 minutes.

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Complete Question

A bee flies at 9 feet per second directly to a flowerbed from its hive. The bee stays at the flowerbed for 13 ​minutes, and then flies directly back to the hive at 6 feet per second. It is away from the hive for a total of 16 minutes. What equation can you use to find the distance of the flowerbed from the hive?

Answer:

The equation is [tex] 960 = \frac{Z}{9}+ \frac{Z}{6} + 780[/tex]

Step-by-step explanation:

From the question we are told that

The velocity of the bee is [tex]v = 9ft/s =[/tex]

The duration on the flowerbed is [tex]t = 13 \ minutes = 780 \ s[/tex]

The velocity back to his hive is [tex]u = 6ft / s[/tex]

The total time away from it hive is [tex]t_t = 16 \ minutes = 960 \ s[/tex]

Now let assume the distance of the flower bed from the hive is Z

Generally the time taken for the bee to travel to the flower bed from its hive is

[tex]t_1 = \frac{Z}{9}[/tex]

The time taken for the bee to fly back to his hive is

[tex]t_2 = \frac{Z}{6}[/tex]

Generally the total time the bee spent outside of his house is mathematically represented as

[tex]t_t = t_1 + t_2 + t[/tex]

=> [tex] 960 = \frac{Z}{9}+ \frac{Z}{6} + 780[/tex]