Answer:
It took 1.2 hours to get to the store
Step-by-step explanation:
Let the time taken to reach the store be t₁
Let the time taken to come back be t₂
Let the speed to and from store = s₁ and s₂ respectively
let the distance to the store = d
To the store:
[tex]speed = \frac{distance}{time} \\s = \frac{d}{t_1} \\t_1 = \frac{d}{s_1}\\t_1 =\frac{d}{4} - - - - - (1)[/tex]
Back from the store:
[tex]s_2 = \frac{d}{t_2} \\t_2 = \frac{d}{s_2}\\where:\\s_2 = 6\ miles\ per\ hour\\t_2 = \frac{d}{6} - - - - - - (2)[/tex]
We are told that total time (t₁ + t₂) = 2 hours
t₁ + t₂ = eqn (1) + eqn (2)
[tex]\frac{d}{4} + \frac{d}{6} = 2\\Multiplying\ through\ by\ 12:\\3d\ +\ 2d\ =\ 24\\5d = 24\\d = \frac{24}{5} \\d = 4.8\ miles[/tex]
∴ length of trip to the store = t₁
from eqn (1)
[tex]t_1 = \frac{d}{4} \\t_1 = \frac{4.8}{4} \\t_1 = 1.2\ hours[/tex]