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please help!! A ball is thrown upward. What is its time interval between the release of the ball and the time it reaches its maximum height? Its initial vertical speed is 10.8 m/s and the acceleration of gravity is 9.8 m/s^2. Neglect air resistance. Answer in units of s.

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MathPhys

Answer:

1.10 s

Explanation:

Given:

v₀ = 10.8 m/s

v = 0 m/s

a = -9.8 m/s²

Find: t

v = at + v₀

0 m/s = (-9.8 m/s²) t + 10.8 m/s

t = 1.10 s

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