Answer:
B. Determine whether (–x)2 – (–x) + 8 is equivalent to x2 – x + 8.
Step-by-step explanation:
on edg 2020 :)
The correct option is Option B: The best way to determine f(x) is an even function is to determine (-x)²-(-x)+8 is equivalent to x²-x+8.
The function which is the same as the reflection in the y-axis is called the even function.
The even function is symmetrical about y-axis.
The value of x and -x is the same in the even function.
Mathematically we can say,
f(-x) = f(x)
Given the function is
f(x)= x²-x+8
In order to check the even of the function f(x)= x²-x+8 replace x by -x.
If it is equivalent to x²-x+8 then f(x) is even function.
Relacing x by -x in the function
f(-x) = (-x)²-(-x)+8
If this expression (-x)²-(-x)+8 is equivalent to x²-x+8 then f(x) is an even function.
f(-x) = (-x)²-(-x)+8
= x²+x+8
≠f(x)
⇒ f(-x) ≠ f(x)
⇒ f(x) is not an even function.
f(x) is now neither an odd function nor an even function.
Therefore the correct option is Option B: The best way to determine f(x) is an even function is to determine (-x)²-(-x)+8 is equivalent to x²-x+8.
Learn more about even function
here: https://brainly.com/question/15315384
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