Answer:
a. [tex]Odds = \frac{3}{7}[/tex]
b. [tex]Odds = \frac{7}{3}[/tex]
Step-by-step explanation:
Given
[tex]n(Black) = 7[/tex]
[tex]n(Grey) = 2[/tex]
[tex]n(White) = 1[/tex]
[tex]n(Total) = 10[/tex]
Solving (a): Odds against winning
Since, the arrow must stop at black, then
The odds against winning is calculated as thus:
[tex]Odds = \frac{n(Total) - n(Black)}{n(Black)}[/tex]
[tex]Odds = \frac{10 - 7}{7}[/tex]
[tex]Odds = \frac{3}{7}[/tex]
Solving (b): Odds in favor of winning
Since, the arrow must stop at black, then
The odds is calculated as thus:
[tex]Odds = \frac{n(Black)}{n(Total) - n(Black)}[/tex]
[tex]Odds = \frac{7}{10 - 7}[/tex]
[tex]Odds = \frac{7}{3}[/tex]