Answer:
The correct is A (A bigger mass of NaCl precipitate will form in Sample #2)
Explanation:
From the question we are told that
The volume of each sample is [tex]V_1 = V_2-V= 250 mL[/tex]
The temperature of sample one is [tex]T_1 = 32^oC[/tex]
The temperature of sample two is [tex]T_2 = 42^oC[/tex]
The depth from where sample two is gotten is [tex]d = 50 \ m[/tex]
The final temperature of the samples is [tex]T_f = 20^oC[/tex]
The final pressure is [tex]P_f = 1atm [/tex]
From the data given we see that the initial temperature of sample 2 is more than sample 1 so more NaCl will be dissolved in 2
Now when both samples are brought to [tex]T_f[/tex] there will be a greater decrease in temperature in sample 2 than in sample 1 so more precipitate of NaCl will be formed in sample 2 than in sample one