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If the temperature of a gas increased from 100K to 200K and the volume of a gas decreased from 20L to 10L, what is the new pressure I’d the original pressure was 100 kPa?

Respuesta :

FaDaReAdEoLa

Answer:

400 kPa

Explanation:

using General Gas Law

[tex] \frac{100 \times 20}{100} = \frac{p \times 10}{200} [/tex]

[tex]p = 400[/tex]

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