Answer:
the three terms can be combined and reduce to:
[tex]6\,x\,y^2\,\sqrt{5\,x}[/tex]
Step-by-step explanation:
Start by extracting all perfect square factors from the square root in order to simplify the terms:
First term: [tex]x\,\sqrt{5\,x\,y^4}=x\,y^2\,\sqrt{5\,x}[/tex]
Second term: [tex]\sqrt{405\,x^3\,y^4} =\sqrt{3^4\,\,5\,\,x^2\,\,x\,y^2\,y^2} =9\,x\,y^2\,\sqrt{5\,x}[/tex]
Third term: [tex]-\sqrt{80\,x^3\,y^4} =-\sqrt{2^4\,\,5\,x\,x^2\,y^2\,y^2} =-4\,x\,y^2\,\sqrt{5\,x}[/tex]
Notice that all of the terms are like terms (contain the same radical part and variable part) so they can be combined:
[tex]\,x\,y^2\,\sqrt{5\,x}+9\,x\,y^2\,\sqrt{5\,x}-4\,x\,y^2\,\sqrt{5\,x}= 6\,x\,y^2\,\sqrt{5\,x}[/tex]
Answer: b on edge2021 6xy^2sqrt 5x
Step-by-step explanation: its on edge and yeah...like me up pls and thank you!
