Suppose that the function g is defined, for all real numbers, as follows.
find g(-5) g(1) g(4)

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Explanation:
The piecewise function shows that we have two cases. Either x = 1 or [tex]x \ne 1[/tex].
If x = 1, then g(x) = 3 as shown in the bottom row. This is why g(1) = 3.
If [tex]x \ne 1[/tex], then g(x) = (1/4)x^2-4
Plug x = -5 into this second definition
g(x) = (1/4)x^2-4
g(-5) = (1/4)(-5)^2-4
g(-5) = (1/4)(25)-4
g(-5) = 25/4 - 4
g(-5) = 25/4 - 16/4
g(-5) = 9/4
Repeat for x = 4
g(x) = (1/4)x^2-4
g(4) = (1/4)(4)^2-4
g(4) = (1/4)(16)-4
g(4) = 4-4
g(4) = 0