bustillostracy bustillostracy
  • 16-08-2020
  • Mathematics
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If h(x)=-(square root) of x-3 (outside square root) plus 5, then what is the value of h(7)?

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valerieulbrich
valerieulbrich valerieulbrich
  • 16-08-2020

Answer:

h(7) = 3

Step-by-step explanation:

h(x) = -[tex]\sqrt{x-3}[/tex] + 5

h(7) = -[tex]\sqrt{(7)-3}[/tex] + 5

h(7) = -√4 + 5

h(7) = -2 + 5

h(7) = 3

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