Answer:
0.76 M
30 g/L
Explanation:
Step 1: Given data
- Molarity of the acid (Ma): 0.175 M
- Volume of the acid (Va): 375 mL
- Molarity of the base (Mb): ?
- Volume of the base (Vb): 86 mL
Step 2: Calculate the molarity of the base
We will use the following expression.
[tex]Ma \times Va = Mb \times Vb\\Mb = \frac{Ma \times Va}{Vb} = \frac{0.175M \times 375mL}{86mL} = 0.76 M[/tex]
Step 3: Calculate the concentration of the base in g/L
The molar mass of NaOH is 40.00 g/mol.
[tex]\frac{0.76mol}{L} \times \frac{40.00g}{mol} = 30 g/L[/tex]
