Answer:
[tex]2ax=v_{2}^{2}-v_{1}^{2}\\2a(\frac{65}{100})=230^{2}-0^{2}\\a=40692\frac{4}{13}m/s^{2}\\\\x=\frac{1}{2} at^{2}\\\frac{65}{100}=\frac{1}{2}(40692\frac{4}{13})t^{2}\\t=0.0101896s[/tex]
I've written all the needed equations for you. All you have to do is some replacements.
Please do not hesitate to ask further questions.
