Answer:
The thrust is [tex]6\times 10^6\ N[/tex]
Explanation:
Given that,
Mass of gas, [tex]m=1.5\times 10^3\ kg[/tex]
The rate at which the gas is expelling, [tex]\dfrac{dv}{dt}=4\times 10^{3}\ m/s[/tex]
We need to find the thrust produced by the gas.
We know that force is equal to the rate of change of momentum. So,
[tex]F=\dfrac{p}{t}[/tex]
Also, p = mv
[tex]F=\dfrac{mv}{t}[/tex]
So,
[tex]F=1.5\times 10^3\times 4\times 10^3\\\\F=6\times 10^6\ N[/tex]
So, the thrust is [tex]6\times 10^6\ N[/tex]
