Answer:
The ball is at a maximum height when t = 0.125s.
Step-by-step explanation:
Vertex of a quadratic function:
Suppose we have a quadratic function in the following format:
[tex]f(x) = ax^{2} + bx + c[/tex]
It's vertex is the point [tex](x_{v}, f(x_{v})[/tex]
In which
[tex]x_{v} = -\frac{b}{2a}[/tex]
If a<0, the vertex is a maximum point, that is, the maximum value happens at [tex]x_{v}[/tex], and it's value is [tex]f(x_{v})[/tex]
In this question:
[tex]h(t) = -32t^{2} + 8t + 3[/tex]
So [tex]a = -32, b = 8[/tex]
When is the ball at a maximum height
[tex]t_{v} = -\frac{8}{2*(-32)} = 0.125[/tex]
The ball is at a maximum height when t = 0.125s.
