An object is dropped from a bridge and allowed to freefall to the ground. The height of the object over time can be modeled using h(t) = 144 – 16t2.

How many seconds will it take the object to reach the ground?

Respuesta :

Answer: *For 2 being an exponent*: 3 seconds

*For 2 being multiplied to t* : 4.5 seconds

Step-by-step explanation:

*For 2 being an exponent*

It says we want to know the time it will take to reach the ground. This means that the height will be 0 at this time.

So we can set h(t) = 0 and solve for t.

[tex]0 = 144 - 16t^2[/tex]

Subtract 144: [tex]-144 = -16t^2[/tex]

Divide -16: [tex]9 = t^2[/tex]

Now square root: [tex]3 = t[/tex]

So it will take 3 seconds to reach the ground.

*For 2 being multiplied to t*

It says we want to know the time it will take to reach the ground. This means that the height will be 0 at this time.

So we can set h(t) = 0 and solve for t.

[tex]0 = 144 - 16t2[/tex]

We can simplify by multiplying the -16 and 2: [tex]0 = 144 - 32t[/tex]

Subtract 144: [tex]-144 = -32t\\[/tex]

Divide by -32: 4.5 = t

So it will take 4.5 seconds to reach the ground.