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A gas has a volume of .880 L at 295 K. What is the temperature of the gas
if its volume is reduced to .625 L., assuming the pressure remains
constant?
310. K
345K
210.K
567 K​

Respuesta :

Answer:

c. 210 K

Explanation:

T2=V2T1/V1

- Hope that helps! Please let me know if you need further explanation.

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