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How many grams of ammonia (NH3) are present in 5.0L of a 0.050M Solution?

A. 5.2g
B. 4.3g
C. 4.3mol
D. 78g

Respuesta :

mahesh11

Answer:

B

Explanation:

NH3 in a liter is 17 x 0.05 = 0.85g

In 5L = 0.85 x 5 = 4.25 = 4.3g

MikeVietnam

Answer:

B. 4.3 g

Explanation:

m = 5.0L x 0.050 mol/L x 17.031 g/mol = 4.26g ~ 4.3g

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Please see the step-by-step solution in the picture attached below.

Hope this answer can help you. Have a nice day!

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