write the equation of the line that is perpendicular to the line y = 2x 2 and passes through the point (6, 3). a. y = 2x 6 b. y = -1/2x 3 c. y = -1/2x 6 d. y = 2x 3
For perpendicular lines, m1m2 = -1 or m2 = -1/m1. Line y = 2x + 2 has a slope of 2, hence required slope is -1/2 Required equation is y - y1 = -1/2(x - x1) y - 3 = -1/2(x - 6) y - 3 = -1/2x + 3 y = -1/2 x + 3 + 3 y = -1/2 x + 6
