find the value of sin(θ) for an angle θ in standard position with a terminal ray that passes through the point (-5, -12)

Answer:
c. -12/13
Step-by-step explanation:
it will be the y-coordinate divided by the distance from the origin, or (-12) / [tex]\sqrt{5^2+12^2}[/tex] = -12/13
Answer:
C. -12/13
Step-by-step explanation:
(-5,-12) is in the third quadrant
So sin would be negative
Hypotenuse = sqrt(5² + 12²)
sqrt(169)
13
sin(theta) = -12/13