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The diagram below shows a horizontal 12.newton force being applied to two blocks, A and B, initially at rest on a horizontal, frictionless surface. Block A has a
mass of 1.0 kilogram and block Bhas a mass of 2.0 kilograms.
F = 12N A 1.0kg B 2.0 kg

Frictionless surface
The magnitude of the acceleration of both blocks is?

A. 6.0 m/s/s
B. 2.0 m/s/s
C. 3.0 m/s/s
D. 4.0 m/s/s

Respuesta :

VeryAvgDillPickle

Answer: D) 4.0 m/s²

Explanation:

a = Fnet / m = 12/3 = 4 m/s²

abidemiokin

Option D is correct The magnitude of the acceleration of both blocks is 4m/s²

According to Newton's second law, the rate of change of momentum is equal to the applied force. Mathematically:

[tex]F_{net}=m_ta[/tex] where:

  • Fnet is the net force acting on both blocks.
  • [tex]m_t[/tex] is the total mass acting on the frictionless surface

Get the total mass

[tex]m_t = m_A + m_B\\m_t = 1.0 + 2.0\\m_t = 3.0kg[/tex]

Fnet = 12N

Substitute the given values into the formula:

Get the acceleration

[tex]a=\dfrac{F_{net}}{m_t} \\a=\dfrac{12}{3}\\ a=4m/s^2[/tex]

Hence the magnitude of the acceleration of both blocks is 4m/s².

Learn more on acceleration here: https://brainly.com/question/10307723

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