A drone is flown, with constant acceleration, in a horizontal plane.
When initially observed, at a point P, it has a velocity of (2i − 7j) ms−1
Four seconds later the drone is at a point Q and has a velocity of (14i + j) ms−1
(i) Find the acceleration of the drone in terms of i and j.

Respuesta :

Answer:

3i + 2j

Step-by-step explanation:

Acceleration = change in velocity/time

Change in velocity

(14i + j) - (2i - 7j)

= 12i + 8j

Divide by time (t = 4)

3i + 2j