Respuesta :
Answer:
1412.2L is the new volume
Explanation:
Given
Volume V1= 697l
Volume V2=?
Temperature t1= 22.9°c
Temperature t2=23.2°c
Pressure P1=754mmHg
Pressure P2=377mmHg
Using.
P1V1/T1=P2V2/T2
V2=P1V1T2/T1P2
754*697*23.2/22.9*377
V2=1412.2l
Answer:
The new volume at this altitude is 1177.3 L
Explanation:
Step 1: Data given
Volume of a helium filled balloon = 697 L
Temperature = 22.9 °C = 295.9 K
Pressure = 754 mmHg
The pressure reduces to 377 mmHg
The temperature decreases to -23.1 °C = 249.9 K
Step 2: Calculate the new volume at this altitude
P1 *V1 / T1 = P2*V2 / T2
⇒with P1 = the initial pressure of the gas = 754 mmHg
⇒with V1 = the initial volume in the balloon = 697 L
⇒with T1 = the initial volume = 295.9 K
⇒with P2 = the reduced pressure = 377 mmHg
⇒with V2 = the new volume = TO BE DETERMINED
⇒with T2 = the decreased temperature = 249.9 K
(754 mmHg* 697 L ) / 295.9 K = (377 mmHg * V2) / 249.9 K
V2 = 1177.3 L
The new volume at this altitude is 1177.3 L
