Respuesta :

[tex]q^3-125=q^3-5^3=(q-5)(q^2+5q+5^2)\\\\=\boxed{(q-5)(q^2+5q+25)}\\\\Used:a^3-b^3=(a-b)(a^2+ab+b^2)[/tex]
ModNov
[tex]a^3 - b^3 = (a - b)(a^2 + ab +b^2) \\ \\\rightarrow g^3 - 125 = g^3 - 5^3 = (g - 5)(g^2+5g+5^2)[/tex]