Respuesta :
so first find the moles of the H₂SO₄: Mass = Moles x RFM
so mass = 5.25 x 98 = 514.5g of H₂SO₄
so to find how many Liters of solution use:
Volume = Density x Grams of solute (per kg +1000)
density = 1.266 x 514.5 +1000 = 1917.357kg/l
now use equation: Conc. = Moles / Volume of solution to find the conc.
Conc. = 5.25 x 1917.357 = 4.39Mol⁻¹
Hope that helps
so mass = 5.25 x 98 = 514.5g of H₂SO₄
so to find how many Liters of solution use:
Volume = Density x Grams of solute (per kg +1000)
density = 1.266 x 514.5 +1000 = 1917.357kg/l
now use equation: Conc. = Moles / Volume of solution to find the conc.
Conc. = 5.25 x 1917.357 = 4.39Mol⁻¹
Hope that helps
molal concentration is expressed as number of moles of solute over kg solvent while molar concentration is expressed as moles solute over liter solution.
In this case, on a basis of 1 kg water, there are 5.25 moles * (98 g/mol) = 514.5 grams H2SO4
The liters solution is equal to
V = (514.5 g + 1000 g H2O) /(ml/1.266g) /1000 = 1.1927 L
Hence the molarity is
5.25 moles/1.1927 L or 4.40 molar.
In this case, on a basis of 1 kg water, there are 5.25 moles * (98 g/mol) = 514.5 grams H2SO4
The liters solution is equal to
V = (514.5 g + 1000 g H2O) /(ml/1.266g) /1000 = 1.1927 L
Hence the molarity is
5.25 moles/1.1927 L or 4.40 molar.