Respuesta :
We are given with a polar equation of r = 6 cos θ and asked to express in rectagular coordinates
r^2 = 6r cosθ
x= r cosθ
r^2 = 6x
x^2+y^2 = 6x
x^2-6x+y^2=0
x^2-6x+9 +y^2=9
(x-3)^2 + y^2=9
The circle has a center at (3,0) and radius of 3.
r^2 = 6r cosθ
x= r cosθ
r^2 = 6x
x^2+y^2 = 6x
x^2-6x+y^2=0
x^2-6x+9 +y^2=9
(x-3)^2 + y^2=9
The circle has a center at (3,0) and radius of 3.