Respuesta :

The values of P₀ and k of the given function are;

P₀ = 194 and k = -1.609

Decay Functions

We are given the function; P = 194(0.2)^(t)

We want to put that function in the form P = P₀e^(kt)

We know that e has a value of approximately 2.7183

Thus, our second equation will be;

P = P₀*2.7183^(kt)   ----(3)

Put P₀*2.7183^(kt) for P in the first equation to get;

P₀*2.7183^(kt) = 194(0.2)^(t)

This means that; P₀ = 194

Now, let us divide the third eq by the first equation to get;

1 = ((0.2)^(t))/(2.7183^(kt))

2.7183^(kt) = (0.2)^(t)

kt In 2.7183 = t In 0.2

kt = -1.609t

k = -1.609

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