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How many grams of water can be produced when 8.73 moles of benzene (C6H6) react with excess oxygen?. . Unbalanced equation: C6H6 + O2 → CO2 + H2O. . Show your solution.

Respuesta :

Willchemistry
2 C6H6 + 15 O2 = 12 CO2 + 6 H2O

2 moles C6H6 -------------------- 6 moles H2O
8.73 moles C6H6 --------------- ( moles H2O)

( moles H2O) = 8.73 x 6 / 2

( moles H2O) = 52.38 / 2

= 26.19 moles of H2O

Molar mass H2O = 18.00 g/mol

1 mole -------------- 18.00 g
26.19 moles ----- ( mass of H2O)

mass of H2O = 26. 19 x 18.00 => 471.42 g of water

hope this helps!


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