Which of the following is the correct graph of the compound inequality 4p + 1 > −7 or 6p + 3 < 33?. . A.a number line with open circles at -2 and 5 with shading in between.. . B.number line with open dots at ¨C2 and 5 and shading to the right of 5 and to the left of ¨C2.. . C.number line with shading everywhere.. . D.number line with open dot at ¨C2 and a closed dot at 5 and shading in between.

break it into 2 inequalities

-13 > -5x + 2 and -5x + 2 > -28 -13-2 > -5x +2-2 -5x > -30 -15 > -5x -5x/(-5) < (-30)/(-5) 3<x x < 6 x>3
Combine the 2 solutions , you'll get 3<x<6
Mark answer on the number line Since it is 'greater than' the 'circle' should not be blacken Perhaps you can try to draw the number line now?

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virtuematane virtuematane · Answer 2 · 2019-05-20T09:04:57+02:00

Answer:

Option: A is the correct answer.

A. a number line with open circles at -2 and 5 with shading in between.

Step-by-step explanation:

We are given a system of linear inequality in terms of variable ''p'' as:

(1) [tex]4p+1>-7[/tex]

on subtracting -1 from both side of the inequality we get:

[tex]4p>-8[/tex]

Now on dividing both side of the inequality by 4 we get:

[tex]p>-2[/tex]

Hence, the region that is obtained is:

(-2,∞)

(2) [tex]6p+3<33[/tex]

on subtracting -3 from both side of the inequality we get:

[tex]6p<30[/tex]

Now on dividing both side of the inequality by 5 we get:

[tex]p<5[/tex]

Hence, the region that is obtained is:

(-∞,5)

Hence, the common region that is obtained by both the inequalities is:

(-2,5)

i.e. the graph will be a number line with open circle both at -2 and 5 and shading in between them.