Respuesta :
The correct answer among the choices presented above is option C. Barium hydroxide is the most basic solution. This can be proved by calculating the concentration of OH- ions in the solution. The one with the highest OH- concentration is the most basic solution.
NH3 is a weak base
NH3 + H2O <=> NH4+ + OH-
Kb = 1.8 x 10^-5 = x^2/0.6-x
x = [OH-]= 0.0033 M
KOH is a strong base so [OH-]= 0.150 M
Ba(OH)2 = Ba2+ + 2 OH-
[OH-]= 2 x 0.100 = 0.200 M
NH3 is a weak base
NH3 + H2O <=> NH4+ + OH-
Kb = 1.8 x 10^-5 = x^2/0.6-x
x = [OH-]= 0.0033 M
KOH is a strong base so [OH-]= 0.150 M
Ba(OH)2 = Ba2+ + 2 OH-
[OH-]= 2 x 0.100 = 0.200 M
The solution which is most basic is c) 0.100 M Ba(OH)₂ , this can be calculated by the concentration of OH- ions.
Calculation for concentartion of OH-:
This can be proved by calculating the concentration of OH- ions in the solution. The one with the highest OH- concentration is the most basic solution.
NH₃ is a weak base
[tex]NH_3 + H_2O < = > NH_4^+ + OH^-[/tex]
[tex]K_b = 1.8 x 10^{-5}\\\\K_b= x^2/0.6-x \\\\x = [OH^-]= 0.0033 M[/tex]
KOH is a strong base.
So, [tex][OH^-]= 0.150 M[/tex]
[tex]Ba(OH)_2 < = > Ba^{2+} + 2 OH^-[/tex]
[tex][OH^-]= 2 * 0.100 = 0.200 M[/tex]
Thus, the solution which is most basic is c) 0.100 M Ba(OH)₂.
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