joanne bought 3 baseball cards for $160. if the first card was as expensive as the combined price of the second and the third cards, and the second card cost $20 more than the third card, what is the price of the first card?
Let the price of the 3rd card be c. Now we can write the equation: c + (c + 20) + (c + c + 20) = 160 .........(1) Simplifying the left hand side of equation (1), we get: 4c + 40 = 160 .........(2) Subtracting 40 from both sides of equation (2) gives: 4c = 120 from which c = $30. Therefore the price of the second card = 30 + 20 = $50 and the price of the first card = 30 + 50 = $80.
