The Frostburg-Truth bus travels on a straight road from Frostburg Mall to Sojourner Truth Park. The mall is 3 miles west and 2 miles south of the City Center. The park is 4 miles east and 5 miles north of the Center. How far is it from the mall to the park to the nearest tenth of a mile?

Respuesta :

If we draw the distances in a Cartesian Plane, Frostburg Mall lies in the point (-3, -2) and Sojourner Truth Park is in (4, 5). Get the distance between the two points,
                               d = √(y2 - y1)² + √(x2 - x1)²
Substituting, 
                                d = √(5 - -2)² + √(4 - -3)²
                                
 d = 9.90 miles
Thus, the distance between the two destinations is approximately 9.9 miles. 

Let

A--------> the coordinates in a Cartesian Plane of Frostburg Mall

B--------> the coordinates in a Cartesian Plane of Sojourner Truth Park

C--------> the coordinates in a Cartesian Plane of City Center (0,0)

Step [tex] 1 [/tex]

Find the coordinates of Frostburg Mall (point A)

we know that

The mall is [tex] 3 [/tex] miles west and [tex] 2 [/tex] miles south of the City Center

so

[tex] x\ coordinate=0-3\\ x\ coordinate=-3 [/tex]

[tex] y\ coordinate=0-2\\ x\ coordinate=-2 [/tex]

Point A is equal to [tex] (-3,-2) [/tex]

Step [tex] 2 [/tex]

Find the coordinates of Sojourner Truth Park (point B)

we know that

The park is [tex] 4 [/tex] miles east and [tex] 5 [/tex] miles north of the City Center

so

[tex] x\ coordinate=0+4\\ x\ coordinate=4 [/tex]

[tex] y\ coordinate=0+5\\ x\ coordinate=5 [/tex]

Point B is equal to [tex] (4,5) [/tex]

Step [tex] 3 [/tex]

Find the distance point A and point B

[tex] A (-3,-2)\ B (4,5) [/tex]

we know that the distance formula is equal to

[tex] d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}} [/tex]

[tex] dAB=\sqrt{(5+2)^{2}+(4+3)^{2}} [/tex]

[tex] dAB=\sqrt{(7)^{2}+(7)^{2}} [/tex]

[tex] dAB=\sqrt{98}} \\ dAB=9.9\ miles [/tex]

therefore

the answer is

The distance from the mall to the park is [tex] 9.9\ miles [/tex]