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An airline knows from experience that the distribution of the number of suitcases that get lost each week on a certain route is approximately normal with μ = 15.5 and σ = 3.6. What is the probability that during a given week the airline will lose more than 20 suitcases?

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Rau7star

Answer:

0.1056

Step-by-step explanation:

z=(x-μ)/σ

as you know, μ=15.5 and σ=3.6

[tex]z=\frac{x-15.5}{3.6}[/tex]

z=1.25

P(x > 20) = P( z > 20) = P(z > 1.25) = normalcdf(1.25 , 100) = 0.1056

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