Answer:
So the value of the test statistic is -0.85.
Step-by-step explanation:
We know that a sample of 1800 computer chips revealed that 53% of the chips do not fail in the first 1000 hours of their use. The company's promotional literature states that 54% of the chips do not fail in the first 1000 hours of their use.
We get that:
[tex]n=1800\\\\p_1=53\%=0.53\\\\p_2=54\%=0.54\\[/tex]
We calculate the standar deviation:
[tex]\sigma=\sqrt{\frac{0.53 \cdot (1-0.53)}{n}}=\sqrt{\frac{0.53 \cdot 0.47}{1800}}=0.01176[/tex]
We calculate the value of the test statistic:
[tex]z=\frac{p_1-p_2}{\sigma}=\frac{0.53-0.54}{0.01176}=-0.85[/tex]
So the value of the test statistic is -0.85.
