[tex]\huge\boxed{y=x-3}[/tex]
Start with point-slope form, where [tex]m[/tex] is the slope and [tex](x_1, y_1)[/tex] is a known point on the line.
[tex]y-y_1=m(x-x_1)[/tex]
Substitute in the known values.
[tex]y-3=1(x-6)[/tex]
Distribute the [tex]1[/tex] to the [tex](x-6)[/tex].
[tex]y-3=x-6[/tex]
Add [tex]3[/tex] to both sides.
[tex]\boxed{y=x-3}[/tex]
Answer:
y=x-3
Step-by-step explanation:
First, you would need to put the information into point-slope form. y-y1=m(x-x1) using the (6,3) as (x1,y1).
It woud look like this: y-3= 1(x-6).
You would get rid of the parenthesis. y-3=x-6.
After this step, you would add 3 to both sides.
This would result in: y=x-3.
