Answer:
35.20 m
Explanation:
By the law of conservation of energy we have,
[tex]mg(H-h)=\frac{1}{2}mv^2[/tex]
[tex]g(H-h)=\frac{1}{2}v^2[/tex]
[tex]\Rightarrow H=\frac{v^2}{2g}+h[/tex]
where m= mass of the skier, h= 3.00 m
D= horizontal distance=13.9 m
H= maximum height attained
Also, the horizontal distance covered by the skier is
D=vt
[tex]=v\frac{2g}{h}[/tex]
[tex]\Rightarrow v^2=\frac{gD^2}{2h}[/tex]
thus, height H in terms of D is given by
[tex]H=\frac{D^2}{2h}+h[/tex]
[tex]H=\frac{13.9^2}{2\times3}+3[/tex]
H=35.20 m
