Respuesta :
Answer:
Gravitational potential energy of the diver is given as 2500 J
Explanation:
As we know that gravitational potential energy is given as
[tex]U = mgh[/tex]
here we know that weight of the diver is given as
[tex]mg = 500 N[/tex]
height of the diver is given as
[tex]h = 5 m[/tex]
so we will have
[tex]U = (500)(5)[/tex]
[tex]U = 2500 J[/tex]
The diver’s gravitational potential energy above ground level is 2500J.
Given the data in the question;
- Weight of diver; [tex]W = 500N[/tex]
- Height above ground; [tex]h = 5m[/tex]
Potential energy is the energy an object posses due to its position relative to other objects. It is expressed as:
[tex]P.E = mgh[/tex]
Where m is the mass of the object, h is its height and g is gravitational acceleration on earth. ( [tex]g = 9.8m/s^2[/tex] )
We know that;
Weight = mass × gravitational acceleration = mg
Hence
[tex]P.E_g = W * h[/tex]
We substitute our given values into the equation
[tex]P.E_g = 500N * 5m\\\\P.E_g = 500kgm/s^2 * 5m\\\\P.E_g = 2500kgm^2/s^2\\\\P.E_g = 2500J[/tex]
Therefore, the diver’s gravitational potential energy above ground level is 2500J.
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