The diver on the diving board in the opening picture weighs 500 Newtons. The diving board is 5 meters above the ground. What is the diver’s gravitational potential energy?

Respuesta :

Answer:

Gravitational potential energy of the diver is given as 2500 J

Explanation:

As we know that gravitational potential energy is given as

[tex]U = mgh[/tex]

here we know that weight of the diver is given as

[tex]mg = 500 N[/tex]

height of the diver is given as

[tex]h = 5 m[/tex]

so we will have

[tex]U = (500)(5)[/tex]

[tex]U = 2500 J[/tex]

The diver’s gravitational potential energy above ground level is  2500J.

Given the data in the question;

  • Weight of diver; [tex]W = 500N[/tex]
  • Height above ground; [tex]h = 5m[/tex]

Potential energy is the energy an object posses due to its position relative to other objects. It is expressed as:

[tex]P.E = mgh[/tex]

Where m is the mass of the object, h is its height and g is gravitational acceleration on earth. ( [tex]g = 9.8m/s^2[/tex] )

We know that;

Weight = mass × gravitational acceleration = mg

Hence

[tex]P.E_g = W * h[/tex]

We substitute our given values into the equation

[tex]P.E_g = 500N * 5m\\\\P.E_g = 500kgm/s^2 * 5m\\\\P.E_g = 2500kgm^2/s^2\\\\P.E_g = 2500J[/tex]

Therefore, the diver’s gravitational potential energy above ground level is  2500J.

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