Sebuah kolom udara memiliki panjang 40cm.Jika garpu kala mempunyai frekuensi 320Hz,maka besarnya cepat rambat gelombang bunyi diudara pada saat resonasi pertama adalah....m/s.

Respuesta :

Answer:

Velocity of sound is 512 m/s

Explanation:

for first resonance condition we know that

[tex]\frac{\lambda}{4} = L[/tex]

[tex]\frac{\lambda}{4} = 0.40[/tex]

[tex]\lambda = 1.6 m[/tex]

now the frequency is given as

[tex]f = 320 Hz[/tex]

now to find the velocity of sound we have

[tex]v = \lambda f[/tex]

[tex]v = 1.6 (320)[/tex]

[tex]v = 512 m/s[/tex]