Respuesta :
Answer:
Days vary for Big Al, his waiting times are both small and large on different visits. Where Trails end seems a more closer number group range. This may be a bias time calculation as one of the restaurants may be more slower or busier at a different time in the week, we are not told the times but 8 visits within one week may not be a true picture as restaurants are open 6-7 days and open days and evenings. 2. Both restaurants have a total mean number of 8, it seems a fair equal amount of visits as the table shows us a waiting scores total 120/8 =8
Step-by-step explanation:
Answer:
a)For this case we are interested on two populations, one is the Big Al's Steak house wait times and the other represent the Trail's End wait times. And we don't know the information about the population but we have two samples of size n =8 described by:
Big Al's Steak house wait times: 5 13 22 7 20 21 20 12
Trail's End wait times: 11 19 14 14 15 20 10 17
b) [tex] \bar X_{BigAl. Hou}= 15[/tex]
[tex] \bar X_{Trial End Wait}= 15[/tex]
Step-by-step explanation:
Part a
For this case we are interested on two populations, one is the Big Al's Steak house wait times and the other represent the Trail's End wait times. And we don't know the information about the population but we have two samples of size n =8 described by:
Big Al's Steak house wait times: 5 13 22 7 20 21 20 12
Trail's End wait times: 11 19 14 14 15 20 10 17
Part b
For this case we can calculate the mean with the following formula:
[tex] \bar X = \frac{\sum_{i=1}^n X_i}{n}[/tex]
And replacing we got:
[tex] \bar X_{BigAl. Hou}= 15[/tex]
[tex] \bar X_{Trial End Wait}= 15[/tex]
