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The magnitudes of the vertical and horizontal components of a vector are 11 and 17 centimeters respectively. Find the magnitude of the vector and the angle from the horizontal axis.

Respuesta :

abustanley5

Explanation:

let the magnitude of the vector be |A|

|A| = ✓11^2 + 17^2 =

|A| =✓410

|A| = 20.23

theta =Tan^-1(11/17) =32.91°

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