Miss C weight before she started her diet is 80 kg.
Solution:
Weight before diet = x
Weight loss percent = 8%
Present weight of Miss C = 73.6 kg
[tex]$ x-x\times \ 8 \% =73.6[/tex]
[tex]$ x-x\times \frac{8}{100} =73.6[/tex]
The denominators must be same to add/subtract the fractions.
LCM of 1 and 100 = 100
Multiply first term by [tex]\frac{100}{100}[/tex] and 73.6 by [tex]\frac{100}{100}[/tex] to make the denominator same.
[tex]$ \frac{100x}{100} - \frac{8x}{100} =\frac{7360}{100}[/tex]
[tex]$ \frac{100x-8x}{100} =\frac{7360}{100}[/tex]
Multiply by 100 on both sides, we get
100x - 8x = 7360
92x = 7360
Divide by 92 on both sides, we get
x = 80
Miss C weight before she started her diet is 80 kg.
