1) Chestnut
2) Sea pine
Step-by-step explanation:
1)
In this problem, we have to calculate the density of the cube.
The density of an object is given by:
[tex]d=\frac{m}{V}[/tex]
where
m is the mass of the cube
V is the volume of the cube
For the wooden cube in this problem, we have:
m = 205 g is the mass
L = 6.2 cm is the length of one side
So, its volume is:
[tex]V=L^3=(6.2)^3=238.3 cm^3[/tex]
Therefore, its density is
[tex]d=\frac{205}{238.3}=0.86 g/cm^3[/tex]
And by comparing this value with the table, we see that this wood is used to make chestnut.
2)
In this problem, we have another cube with a mass of
m = 68.75 g
We also know that the cube has a side measuring a whole number of centimeters.
Let's call the length of one side as L.
We have to try several attempts to find the correct value of L.
Let's start with 6 cm:
L = 6 cm
So the volume is
[tex]V=L^3=6^3=216 cm^3[/tex]
In this case, the density would be
[tex]d=\frac{m}{V}=\frac{68.75}{216}=0.32 g/cm^3[/tex]
This value is lower than all the values in the table, so we have to try with a smaller volume.
The next lower integer length for the cube is
L = 5 cm
which leads to a volume of
[tex]V=L^3=5^3=125 cm^3[/tex]
In this case, the density is
[tex]d=\frac{68.75}{125}=0.55 g/cm^3[/tex]
Which matches with the density of sea pine.
