Respuesta :
Answer:
[tex]V=0.48L[/tex]
Explanation:
Hello,
In this case, the rest of statement is missing, therefore, it was found to be:
We add 100 ml of 0.01 M Na₂SO₄-solution to 100 ml of 0.02 M CaCl₂-solution. A precipitate of CaSO₄ is formed. What is the (minimal) volume of 0.01 M Na₂SO₄-solution that needs to be added to the mix for the CaSO₄ precipitate to be just dissolved completely? Consider CaSO₄ solubility constant to be 2.5x10⁻⁵
In this case, Ca⁺², SO₄⁻² and H₂O are out interest substance, thus, if we introduce [tex]V[/tex] as the additional volume of Na₂SO₄-solution, we've got:
[tex]V_T= V+0.2L[/tex]
[tex]n_{SO_4^{-2}}=(V+0.1 L)(0.01 \frac{mol}{L})[/tex]
[tex]n_{Ca^{+2}}=(0.1 L)(0.02\frac{mol}{L} )[/tex]
Hence, we have:
[tex]Ksp=[Ca^{+2}][SO_4^{-2}]=\frac{n_{Ca^{+2}}*n_{SO_4^{-2}}}{V_T} =2.5x10^{-5}[/tex]
Replacing the previous values:
[tex]2.5x10^{-5}=\frac{(0.1L)(0.02\frac{mol}{L} )}{V+0.2L} \frac{(V+0.1L)(0.01\frac{mol}{L} )}{V+0.2L}[/tex]
Solving for [tex]V[/tex], we obtain:
[tex]V=0.48L[/tex]
Best regards.
The volume needed for Sodium sulfate solution is 0.48 Litres. When sodium sulfate reacts with copper chloride, copper sulfate is formed.
Reaction between sodium sulfate and copper chloride:
When sodium sulfate reacts with copper chloride, copper sulfate is formed. This reaction is known as double decomposition reaction and a precipitate of Copper sulfate makes it precipitaion reaction too.
When we add 100 ml of 0.01 M Na₂SO₄-solution to 100 ml of 0.02 M CaCl₂-solution.
A precipitate of CaSO₄ is formed.
Consider CaSO₄ solubility constant to be 2.5x10⁻⁵
In this case, Ca⁺², SO₄⁻² and H₂O are the following cations and species involved, Thus, if we introduce as the additional volume of Na₂SO₄-solution, we've got:
Total Volume = V+0.2 L
n for Sulfate ion = V+0.1 L*0.01 mol/L
n for Calcium ion = 0.1L*0.02 mol/L
The solubility product will be: [tex]2.5*10^{-5}\\\\[/tex]
On solving:
We will get, V=0.48 L
Find more information about Solubility product here:
brainly.com/question/9807304
