Answer:
Width of the Rectangular Tin=8 inch
Length of the Rectangular Tin= 16 inch
Step-by-step explanation:
Let the Width of the Rectangle=W
The length of the piece of tin is twice the width, Length = 2W
Since Squares of 3 inch are cut from all four corners of the rectangle
Length of the box = 2W-(3+3)=(2W-6) inches
Breadth of the Box = W-(3+3)=(W-6) inches
Height = 3 inches
Volume of the box = 60 cubic inches
Now, Volume of a cuboid=lbh
3(2W-6)(W-6)=60
Divide both sides by 3
(2W-6)(W-6)=20
Expanding the brackets
[tex](2W-6)(W-6)=20\\2W^2-12W-6W+36=20\\2W^2-18W+36-20=0\\2W^2-18W+16=0[/tex]
Factorizing
[tex]2W^2-16W-2W+16=0\\2W(W-8)-2(W-8)=0\\(W-8)(2W-2)=0\\W-8=0 , 2W-2=0\\W=8, 1[/tex]
Since the Width cannot be less than 6,
Width of the Rectangular Tin=8 inch
Length= 2 X 8 = 16 inch
