A pebble drops from a balcony that is 160 feet above the ground. The pebble lands on the top of a sign that is 16 feet high. The function y=160-16t^2 represents the height y (in feet) of the pebble t seconds after dropping from the balcony. How many seconds does the pebble drop before hitting the sign?

Respuesta :

Answer:

3 seconds

Step-by-step explanation:

16 = 160 - 16t²

16t² = 144

t² = 9

t = 3

Velocity is the rate of change of the the position of a object with respect to the time. Total seconds the pebble drop before hitting the sign is 3 seconds.

Given-

A pebble drops from a balcony which is 160 feet above the ground.

Given function for the height is,

[tex]y=160-16t^2[/tex]

To know this we know about the velocity.

What is velocity?

Velocity is the rate of change of the the position of a object with respect to the time.

Now it is given in the question that the pebbles land on the top of a sign which has 16 feet above the ground.

Thus keep this value of y in the above equation to find the time.[tex]16=160-16t^2[/tex]

divide both side by 16, we get,

[tex]1=10-t^2[/tex]

Rearrange the equation for t,

[tex]t^2=10-1[/tex][tex]t^2=9[/tex]

[tex]t=3[/tex]

Hence, total seconds the pebble drop before hitting the sign is 3 seconds.

For more about the time follow the link below;

https://brainly.com/question/2570752