Answer:
Volume of an analyte solution is 60 mL.
30 mg is the mass of unknown acid was present in an analyte.
Explanation:
According to question , 120 mL of unknown acid solution was mixed with 20 NaOH solution to reach its endpoint.
Then 10 mL of NaOH will bring the end point of :
[tex]\frac{120}{20}\times 10 mL=60 mL[/tex] unknown acid solution.
Volume of an analyte solution is 60 mL.
Mass of unknown acid = 60 mg
Volume of the solution of unknown acid = 120 mL
Concentration of unknown acid acid solution:
= [tex]\frac{60 mg}{120 mL}=0.5 mg/mL[/tex]
Then 60 mL of unknown acid solution will have:
[tex]60 mL\times 0.5 mg/mL=30 mg[/tex]
30 mg is the mass of unknown acid was present in an analyte.
The mass of the analyte to take 10 mL of NaOH to reach the endpoint is 30 mg. The volume of the analyte in solution is 60 mL
Titration is a chemical analysis procedure that uses a solution of known concentration to estimate the concentration of an unknown solution.
Given that:
60 mg of an unknown acid in 120 mL water is used to neutralize 20 mL of NaOH.
Now, if 10 mL of NaOH is used, the amount of acid that would be neuralized will be half the initial amount.
= 60 mg × 1/2
= 30 mg
The volume of the analyte is computed as:
= (120mL / 20mL) × 10 mL
= 6 × 10 mL
= 60 mL
Learn more about titration here:
https://brainly.com/question/23307058?referrer=searchResults
